Voltage is the energy per unit charge created by the separation. Thus, the voltage V₁₂ between two point 1 and 2 in an electric circuit is the energy or work needed to move a unit charge from 1 to 2. We express this ratio in differential form as :-
v=V₁₂=dw/dq................ (1.3)
where,
w=the energy in joule
q=the charge in coulombs
v=V₁₂=the voltage in volts
From equation (1.3) it is evident that
1 volt=1 joule/coulomb=1 newton-meter/coulomb
1 volt=1 joule/coulomb=1 newton-meter/coulomb
Thus, voltage or potential difference is the energy required to move a unit charge through an element.
The plus (+) and minus (-) sign s are used to represent reference direction or voltage polarity. The voltage V₁₂ can be interpreted in two ways.
- Point 1 is at a potential of V₁₂ volts higher than point 2.
- The potential at point 1 with respect to potential 2 is V₁₂.
Therefore, logically it follows that,
In figure (a), point 1 is +10V above point 2; in figure (b), point 2 is -10V above point 1. We can say that in figure (a) there is a 10V voltage drop from point 1 to 2 or equivalently a 10V voltage rise from point 2 to 1. In general, a voltage drop from 1 to 2 is equivalent to a voltage rise from 2 to 1.
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